当前位置:七道奇文章资讯编程技术Java编程
日期:2011-03-22 16:16:00  来源:本站整理

RSA算法的实现(java版)[Java编程]

赞助商链接



  本文“RSA算法的实现(java版)[Java编程]”是由七道奇为您精心收集,来源于网络转载,文章版权归文章作者所有,本站不对其观点以及内容做任何评价,请读者自行判断,以下是其具体内容:

package rsa; import java.math.BigInteger;

public class RSA {
private long p,q,e,d,n;
public RSA(){
int pIndex = (int)(Math.random()*10);
int qIndex;
int eIndex;
do{
qIndex = (int)(Math.random()*10);
}
while(qIndex==pIndex);
do{
eIndex = (int)(Math.random()*10);
}
while(eIndex==pIndex||eIndex==pIndex);
p = 1033;
q = 2017;
e = 29437;
n = p*q;
d = calculateD();
}
private long calculateD(){
long t0 = 0,t1 = 1,t2 = -1;
long r0 = (p-1)*(q-1), m = r0,r1 = e ,r2 = -1;
do{
long q = r0/r1;
r2 = r0-r1*q;
if(r2==0)break;
t2 = t0 - t1*q;
while(t2<0){
t2+=m;
}
if(t2>=m){
t2 %= m;
}
r0 = r1;
r1 = r2;
t0 = t1;
t1 = t2;
}while(r2!=0);
if(r1!=1){
return 0;
}
else{
return t2;
}
}

public long getE() {
return e;
}
public long getN() {
return n;
}
public long getD() {
return d;
}
public BigInteger encode(BigInteger data){
return pow(data,d).mod(new BigInteger(n+""));
}
public BigInteger decode(BigInteger code){
return pow(code,e).mod(new BigInteger(n+""));
}
public BigInteger pow(BigInteger data,long p){
data = data.pow((int)p);
return data;
}
public static void main(String args[]){
RSA rsa = new RSA();

BigInteger data = new BigInteger("222222");
long oldtime = System.currentTimeMillis();
BigInteger code = rsa.encode(data);
long newtime = System.currentTimeMillis();
double codetime = ((double)(newtime-oldtime))/1000;
oldtime = System.currentTimeMillis();
BigInteger decode = rsa.decode(code);
newtime = System.currentTimeMillis();
double decodetime = ((double)(newtime-oldtime))/1000;
System.out.println("privateKey:"+rsa.d);
System.out.println("publickKey:"+rsa.e);
System.out.println("N:"+rsa.n);
System.out.println("data:"+data);
System.out.println("code:"+code+" time:"+codetime);
System.out.println("decode:"+decode+" time:"+decodetime);

}

}


  以上是“RSA算法的实现(java版)[Java编程]”的内容,如果你对以上该文章内容感兴趣,你可以看看七道奇为您推荐以下文章:
  • RSA算法的实现(java版)
  • 本文地址: 与您的QQ/BBS好友分享!
    • 好的评价 如果您觉得此文章好,就请您
        0%(0)
    • 差的评价 如果您觉得此文章差,就请您
        0%(0)

    文章评论评论内容只代表网友观点,与本站立场无关!

       评论摘要(共 0 条,得分 0 分,平均 0 分) 查看完整评论
    Copyright © 2020-2022 www.xiamiku.com. All Rights Reserved .