SQL的Join利用图解教程[MSSQL防范]

SELECT * FROM TableA
INNER JOIN TableB
ON TableA.name = TableB.name

id name id name
-- ---- -- ----
1 Pirate 2 Pirate
3 Ninja 4 NinjaInner join
产生的后果集合,是A和B的交集.

SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name

id name id name
-- ---- -- ----
1 Pirate 2 Pirate
2 Monkey null null
3 Ninja 4 Ninja
4 Spaghetti null null
null null 1 Rutabaga
null null 3 Darth VaderFull outer join 产生A和B的并集.但是需求注意的是,关于没有匹配的记录,则会以null做为值.

SELECT * FROM TableA
LEFT OUTER JOIN TableB
ON TableA.name = TableB.name

id name id name
-- ---- -- ----
1 Pirate 2 Pirate
2 Monkey null null
3 Ninja 4 Ninja
4 Spaghetti null nullLeft outer join 产生表A的完好集,而B表中匹配的则有值,没有匹配的则以null值代替.

SELECT * FROM TableA
LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE TableB.id IS null

id name id name
-- ---- -- ----
2 Monkey null null
4 Spaghetti null null产生在A表中有而在B表中没有的调集.

SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE TableA.id IS null
OR TableB.id IS null

id name id name
-- ---- -- ----
2 Monkey null null
4 Spaghetti null null
null null 1 Rutabaga
null null 3 Darth Vader产生A表和B表都没有呈现的数据集.