三种获得指定文件夹下全部的文件名称办法[网站编程]

返回包含文件名的途径.然后再截取文件名

如:

string[]   filenames=directory.getfiles(path);
for(string   files   in   filenames)
{
response.write(files.replace(path,""));
}

办法二:

directoryinfo   dir   =   new   directoryinfo(@"c:data");
                fileinfo[]   finfo   =   dir.getfiles();
                string   fnames   =   string.empty;
                for   (int   i   =   0;   i   <   finfo.length;   i++)
                {
                        fnames   +=   finfo[i].name   +   " <br> ";
                }
                response.write(fnames);

办法三

/// <summary>
/// 获得指定文件夹下全部的文件名称
/// </summary>
/// <param name="foldername">指定文件夹名称,绝对途径</param>
/// <param name="filefilter">文件范例过滤,按照文件后缀名,如:*,*.txt,*.xls</param>
/// <param name="iscontainsubfolder">能否包含子文件夹</param>
/// <returns>arraylist数组,为全部需求的文件途径名称</returns>
public static arraylist getallfilesbyfolder(string foldername, string filefilter,bool iscontainsubfolder)
{
arraylist resarray = new arraylist ();
string[] files = directory.getfiles(foldername, filefilter);
for (int i = 0; i < files.length ; i++)
{
resarray.add(files[i]);
}
if (iscontainsubfolder)
{
string[] folders = directory.getdirectories(foldername);
for (int j = 0; j < folders.length; j++)
{
//遍历全部文件夹
arraylist temp = getallfilesbyfolder(folders[j], filefilter, iscontainsubfolder);
resarray.addrange(temp);
} 
}
return resarray;
}

/// <summary>
/// 获得指定文件夹下全部的文件名称,不过滤文件范例
/// </summary>
/// <param name="foldername">指定文件夹名称,绝对途径</param>
/// <param name="iscontainsubfolder">能否包含子文件夹</param>
/// <returns>arraylist数组,为全部需求的文件途径名称</returns>
public static arraylist getallfilesbyfolder(string foldername, bool iscontainsubfolder)
{
return getallfilesbyfolder(foldername, "*", iscontainsubfolder);
}